Determinant of a 2×2 Matrix

Suppose we are given a square matrix A with four elements: a, b, c, and d.

The **determinant of matrix A** is calculated as

If you can’t see the pattern yet, this is how it looks when the elements of the matrix are color-coded.

- We take the product of the elements
**from top left to bottom right,**then subtract by the product of the elements**from top right to bottom left**.

If you want additional practice problems on finding the determinant of a 2×2 matrix, please click the link below.

**Determinant of 2×2 Matrix Practice Problems with Answers**

## The Determinant of 2 x 2 Matrix (animated)

### Examples of How to Find the Determinant of a 2×2 Matrix

**Example 1:** Find the determinant of the matrix below.

This is an example where all elements of the 2×2 matrix are positive.

**Example 2:** Find the determinant of the matrix below.

Here is an example of when all elements are negative. Make sure to apply the basic rules when multiplying integers. Remember, the product of numbers with the same sign will always be positive. On the contrary, if the signs are different the product will be negative.

**Example 3:** Evaluate the determinant of the matrix below.

Make sure to remember the rules on how to subtract integers. That is, when you subtract integers, you change the operation from subtraction to addition but you must switch the sign of the number directly found to its right (it’s called the

**Example 4:** Evaluate the determinant of the matrix below.

You may also encounter a problem where some of the elements in the matrix are variables. Treat this just like a normal determinant problem. Plug those variables in the designated spots in the formula then simplify as usual.

**Example 5**: Find the value of \color{red}\large{x} in the matrix below if its determinant has a value of -12.

This is not a “trick” question. We can actually find the value of x such that when we apply the formula we get -12.

Get the determinant of the given matrix then set it equal to -12. By doing so, we generate a simple linear equation that is solvable for x.

Checking our answer:

Replace \color{red}\large{x} by 7, then calculate the determinant. We expect to get -12.

This verifies that our solution is correct!

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