Sum of Consecutive Integers Word Problems

When solving word problems involving consecutive integers, it’s important to remember that we are looking for integers that are one unit apart.

So if we have [latex]n[/latex] as the first integer, then [latex]n + 1[/latex] will be the second integer, [latex]n + 2[/latex] will be the third integer, [latex]n + 3[/latex] will be the fourth, [latex]n + 4[/latex] will be the fifth, and so on.

a diagram showing n as the first integer, the quantity n plus 1 as the second integer, the quantity n plus 2 as the third integer, the quantity n plus 3 as the fourth integer, the quantity n plus 4 as the fifth integer, and so forth

Let’s take for example: [latex]15[/latex], [latex]\left( {15 + 1} \right)[/latex], [latex]\left( {15 + 2} \right)[/latex], [latex]\left( {15 + 3} \right)[/latex], [latex]\left( {15 + 4} \right)[/latex]

Our results come up to: [latex]15,\,16,\,17,\,18,\,19[/latex]


When dealing with consecutive integers, notice that the difference between the larger and smaller integers is always equal to [latex]1[/latex].

Observe the following:

  • [latex]\left( {n + 1} \right) – \left( n \right) = n + 1 – n = n – n + 1 = 1[/latex]
  • [latex]\left( {n + 2} \right) – \left( {n + 1} \right) = n + 2 – n – 1 = n – n + 2 – 1 = 1[/latex]
  • [latex]\left( {n + 3} \right) – \left( {n + 2} \right) = n + 3 – n – 3 = n – n + 3 – 2 = 1[/latex]
  • [latex]\left( {n + 4} \right) – \left( {n + 3} \right) = n + 4 – n – 3 = n – n + 4 – 3 = 1[/latex]

Examples of Solving the Sum of Consecutive Integers

Example 1: The sum of three consecutive integers is [latex]84[/latex]. Find the three consecutive integers.

The first step to solving word problems is to find out what pieces of information are available to you.

For this problem, the following facts are given:

  • We need to ADD three integers that are consecutive
  • The numbers are one unit apart from each other
  • Each number is one more than the previous number
  • The sum of the consecutive integers is [latex]84[/latex]

With these facts at hand, we can now set up to represent our three consecutive integers.

Let [latex]n[/latex] be our first integer. Therefore,

the first integer is n, the second integer is n plus 1 while the third integer is n plus 2

We’re now ready to write our equation. Remember that we are given the sum, so we will be adding our three consecutive integers.

n plus the quantity n plus 1, plus the quantity n plus 2 is equal to 84

Let’s proceed and solve the equation.

the value of n is 27

Now that we have the value for the variable “[latex]n[/latex], we can use this to identify the three consecutive integers.

the first integer is 27, the second integer is 28, and the third integer is 29

Finally, let’s do a quick check to make sure that the sum of the consecutive integers [latex]27[/latex], [latex]28[/latex], [latex]29[/latex] is indeed [latex]84[/latex] as given in our original problem.

27 plus 28 plus 29 is equal to 84

Example 2: Find four consecutive integers whose sum is [latex]238[/latex].

To start, let’s go ahead and determine the important facts that are given in this problem.

  • We will be adding four successive integers
  • The adjacent integers are one unit apart
  • The sum of the four consecutive integers is [latex]238[/latex]

The next step is to represent the four consecutive integers using the variable “[latex]n[/latex]”.

Let [latex]n[/latex] be the first integer. Since the four integers are consecutive, this means that the second integer is the first integer increased by 1 or [latex]{n + 1}[/latex]. In the same manner, the third integer can be represented as [latex]{n + 2}[/latex] and the fourth integer as [latex]{n + 3}[/latex].

the first integer is n, the second integer is n plus 1, the third integer is n plus 2, and the fourth integer is n plus 3.

We can then translate “the sum of four consecutive integers is [latex]238[/latex]” into an equation.

n plus the quantity n plus 1, plus the quantity n plus 2, plus the quantity n plus 3, is equal to 238

Solve the equation:

in the equation, n plus n plus 1, plus n plus 2, plus n plus 3 is equal to 238, the value of n is 58.

At this point, the value of [latex]n[/latex] is not our final answer. We will use this value, however, to find the other three integers that follow after [latex]n[/latex] which is [latex]58[/latex].

the first integer is 58, the second integer is 59, the third integer is 60, and the fourth integer is 61.

The last condition that we need to satisfy is that the sum of the four consecutive integers must be [latex]238[/latex]. Obviously, since “sum” means to add, we will be adding the integers [latex]58[/latex], [latex]59[/latex], [latex]60[/latex], and [latex]61[/latex].

58 plus 59 plus 60 plus 61 is equal to 238

Example 3: The sum of six consecutive integers is [latex] – \,9[/latex]. What are the integers?

What do we know?

  • We will add six consecutive integers
  • The sum of the integers is [latex] – \,9[/latex]
  • The consecutive integers are one unit apart
  • Since the sum of the consecutive integers is a negative number, more likely, the sequence of integers will involve negative integers

Represent the six consecutive integers. This time, we’ll use [latex]x[/latex] as our variable.

Let [latex]x[/latex] be the 1st integer.

the first integer is x, the second integer is x plus 1, the third integer is x plus 2, the fourth integer is x plus 3, the fifth integer is x plus 4, and the sixth integer is x plus 5.

Next, let’s translate “the sum of six consecutive integers is [latex] – \,9[/latex]” into an equation.

[latex]x[/latex] + [latex]\left( {x + 1} \right)[/latex] + [latex] \left( {x + 2} \right)[/latex] + [latex]\left( {x + 3} \right)[/latex] + [latex]\left( {x + 4} \right)[/latex] + [latex]\left( {x + 5} \right)[/latex] = [latex]- \,9[/latex]

Solve:

in the equation 6x plus 15 is equal to negative 9; the value of x is negative 4

Now that we know the value of [latex]x[/latex] which is [latex]- \,4[/latex], let’s determine the six consecutive integers.

the first integer is negative 4, the second integer is negative 3, the third integer is negative 2, the fourth integer is negative 1, the fifth integer is zero, and the sixth integer is 1.

As you can see, our six consecutive integers are [latex]- \,4[/latex], [latex]- \,3[/latex], [latex]- \,2[/latex], [latex]- \,1[/latex], [latex]0[/latex], and [latex]1[/latex]. The only thing left for us to do is to check if the sum of the consecutive integers is indeed [latex]- \,9[/latex].

negative 4 plus negative 3 plus negative 2 plus negative 1 plus zero plus 1 is equal to negative 9.

Example 4: The sum of three consecutive integers is [latex]- \,90[/latex]. What is the largest integer?

This is a type of problem where you need to be careful. Most of the time, we are only asked to find the consecutive integers which when added, must give the specified sum. In this case, however, we not only have to find the three consecutive integers but also determine which among the three integers is the largest. The rule of thumb is to always read the problem carefully and pay close attention to what is asked.

No matter how straightforward a problem is, it’s still good practice to always identify what facts are available to you. Think of these pieces of information as your compass showing you directions on how to solve the problem.

What we know:

  • We will be adding three integers that are consecutive
  • We should get a sum of [latex]- \,90[/latex] when we add the three integers
  • The consecutive or adjacent integers only differ by one unit
  • It is likely that we will be dealing with negative integers

Proceed by representing the consecutive integers.

Let [latex]\textbf{\textit{n}}[/latex], [latex]\textbf{\textit{n+1}}[/latex] and [latex]\textbf{\textit{n+2}}[/latex] be the three consecutive integers.

a table showing the first integer represented by n in the first column, the second integer represented by n plus 1 in the second column, and the third integer is represented by n plus 2 in the third column.

Now, let’s write the equation by translating the math sentence, “the sum of three consecutive integers is [latex]- \,90[/latex]” and solve for [latex]n[/latex].

the value of n in the equation, n plus the quantity n plus 1, plus the quantity n plus 2 is negative 31.

Since [latex]n = – \,31[/latex], then the three consecutive integers are [latex]- \,31[/latex], [latex]- \,30[/latex], and [latex]- \,29[/latex].

the first integer n is negative 31; the second integer, n plus 1, is negative 30, and the third integer, n plus 2, is negative 29.

Do they total to [latex]- \,90[/latex] when added? Lets’s take a look.

negative 31 plus negative 30 plus negative 29 is equal to negative 90

If we’re not paying attention, we will usually stop right here because we now have our integers and we got a sum of [latex]- \,90[/latex] when we added them.

But as you know, we’re not done yet! Our problem asked us to identify which among the three consecutive integers: [latex] – \,31[/latex], [latex] – \,30[/latex], and [latex] – \,29[/latex] is the largest.

Therefore, our final answer is [latex]- \,29[/latex].


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Sum of Consecutive Even Integers Word Problems

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